🧬Biology · Year 11

Final Assessment

You have done the four days. This is where you find out what actually stuck. Do it in one sitting, without scrolling back — that is the whole point.

总测验(全英文)· 四天学完后做,检验掌握程度
题目一律英文,Phoebe 只读英文。选择题点一下即时判分并给英文解析;简答题先自己写,再点开满分答案逐条对得分点(得分点中文说明在「中文注释」里)。

Part A · Multiple Choice 15 questions

1A DNA molecule is a polymer built from many repeating units called nucleotides. Which three components make up ONE nucleotide?
Every nucleotide has exactly three parts: a phosphate group, a deoxyribose sugar and ONE nitrogenous base (A, T, C or G). Option B names ribose, which is not the sugar found in DNA. Option C describes two bases on one sugar, which does not exist. Option D confuses components of a nucleotide with a base pair (which needs nucleotides on two different strands) and with a hydrogen bond, which is a bond, not a building block.
每个核苷酸 (nucleotide) 恰好由三部分组成:磷酸基团 (phosphate group)、脱氧核糖 (deoxyribose sugar)、以及一个含氮碱基 (nitrogenous base)(A、T、C 或 G 中的一个)。B 写的是核糖 ribose,那不是 DNA 里的糖。C 说一个糖上接两个碱基,不存在这种结构。D 把"零件"和"连接方式"搞混了:碱基对 (base pair) 需要两条链上的两个核苷酸才能形成,氢键 (hydrogen bond) 是一种化学键,不是核苷酸的组成部分。
2Which statement about interphase is correct?
Interphase (G1, S and G2) occupies most of the cell cycle and is the busiest part of it: the cell grows, makes organelles and proteins, and replicates its DNA. It is not a 'rest' stage. It is also not part of mitosis at all - it is the part of the CELL CYCLE that comes before M phase. Chromosomes stay as long, uncondensed chromatin threads during interphase; condensation happens in prophase.
(分裂)间期 (interphase) 包含 G1 期、S 期、G2 期,占细胞周期 (cell cycle) 的绝大部分时间,而且是最忙的阶段:细胞生长、合成细胞器 (organelle) 和蛋白质,并完成 DNA 复制 (DNA replication)。它绝不是"休息期"(这是最常见的错误说法)。它也不属于有丝分裂 (mitosis),而是细胞周期中位于 M 期 (M phase) 之前的阶段。间期里 DNA 以细长的染色质 (chromatin) 形式存在,只有到了前期 (prophase) 才会螺旋缩短成显微镜下可见的染色体 (chromosome)。
3State the outcome of mitosis followed by cytokinesis in a human somatic cell.
Mitosis divides the nucleus and cytokinesis divides the cytoplasm, producing TWO daughter cells that are genetically identical to each other and to the parent cell, and that keep the parent's chromosome number (diploid, 46 in humans). The other three options import meiosis logic - four cells, halving of chromosome number, genetic variation - none of which happens in mitosis.
有丝分裂 (mitosis) 分的是细胞核,胞质分裂 (cytokinesis) 分的是细胞质,最终产生 2 个子细胞 (daughter cell):它们彼此之间、以及与亲代细胞之间遗传物质完全相同 (genetically identical),染色体数目不变,仍是二倍体 (diploid)(人 46 条)。另外三个选项都是把减数分裂 (meiosis) 的特征硬套进来了——4 个细胞、染色体减半、产生差异——有丝分裂一样都不会发生。
4Which statement about complementary base pairing in DNA is correct?
The pairing rule is fixed: A-T and C-G. The two bases of a pair are held together by weak hydrogen bonds (2 between A and T, 3 between C and G). Option B breaks the pairing rule. Option C names the wrong bond - covalent bonds hold the sugar-phosphate backbone together, not the base pair; if the bases were covalently bonded the helix could not unzip. Option D is the 'it just has to fit' misconception: pairing is specific, not merely a matter of size.
配对规则是固定的:腺嘌呤 (adenine) 只配胸腺嘧啶 (thymine),胞嘧啶 (cytosine) 只配鸟嘌呤 (guanine),即 A-T、C-G。配对的两个碱基之间靠弱的氢键 (hydrogen bond) 相连(A-T 之间 2 个,C-G 之间 3 个)。B 违反配对规则。C 用错了键:共价键 (covalent bond) 连的是磷酸—脱氧核糖骨架 (sugar-phosphate backbone);如果碱基之间是共价键,双螺旋 (double helix) 就"拉不开"了。D 是"只要大小塞得下就行"的误解——配对是专一的,不是随便凑。
5DNA replication is described as semi-conservative. What does this mean?
'Semi-conservative' means half of each new double-stranded molecule is conserved (kept) from the parent molecule: one whole original strand acts as a template and pairs with one whole new strand. Option B splits each individual strand into old and new halves, which is not what happens. Option C is the conservative model, which Meselson and Stahl's evidence ruled out. Option D discards the original strands entirely, which contradicts the word 'semi-conservative'.
"半保留"的意思是:每个新形成的双链 DNA 分子中,有一半是从亲代分子"保留"下来的——一条完整的原有链作为模板链 (template strand),与一条完整的新合成子链 (daughter strand) 配对。B 是把"每一条链"切成一半旧一半新,这是对"半保留"的经典误读。C 是全保留模型(一个分子全旧、一个分子全新),已被 Meselson-Stahl 实验的证据否定。D 把原有链全部丢弃,和"半保留"直接矛盾。
6Which statement best describes what happens during S phase of the cell cycle?
S phase is the DNA synthesis (replication) phase of interphase. After it, every chromosome is still ONE chromosome but is now made of two identical sister chromatids joined at a centromere. Option B describes prophase, option C describes G1, and option D describes anaphase. Note that replication is finished before mitosis starts - it never happens 'during prophase'.
S 期(合成期)(S phase) 是(分裂)间期 (interphase) 中进行 DNA 复制 (DNA replication) 的阶段。复制完成后,每条染色体 (chromosome) 仍然算 1 条染色体,但已由 2 条完全相同的姐妹染色单体 (sister chromatid) 组成,二者在着丝粒 (centromere) 处相连。B 说的是前期 (prophase),C 说的是 G1 期,D 说的是后期 (anaphase)。请牢记:复制在有丝分裂开始之前就已全部完成,绝不会"在前期才复制"。
7Which statement correctly contrasts cell division in bacteria with mitosis in a human cell?
Prokaryotes do not undergo mitosis. They divide by binary fission: the single circular chromosome is copied, the copies move apart, and the cell divides - with no nucleus, no nuclear envelope to break down and no spindle fibres. Option B repeats the common error that bacteria 'do mitosis'. Option C invents four daughter cells; binary fission gives two, normally genetically identical. Option D is wrong because the chromosome IS copied first - otherwise the daughter cells would not both get a full set of genes.
原核生物(细菌)不进行有丝分裂 (mitosis),而是进行二分裂 (binary fission):那条唯一的环状染色体先复制,两份拷贝分开,细胞随后一分为二——全程没有细胞核 (nucleus)、没有核膜 (nuclear envelope) 解体、也没有纺锤丝(纺锤体)(spindle fibre)。B 是"细菌也做有丝分裂"这个常见错误。C 凭空多出 4 个子细胞;二分裂产生 2 个、通常遗传物质相同的子细胞。D 错在染色体其实是先复制的,否则两个子细胞不可能各得一整套基因。
8One strand of a short section of DNA has the base sequence: T - A - C - G - G - C - A - T. What is the base sequence of the complementary strand?
Apply A-T and C-G base by base: T pairs A, A pairs T, C pairs G, G pairs C, G pairs C, C pairs G, A pairs T, T pairs A, giving A-T-G-C-C-G-T-A. Option B is simply the same sequence copied, the classic 'copy not complement' error. Option C leaves C opposite C and G opposite G at positions 3 and 4. Option D breaks the rule at the last two positions (A opposite A, T opposite T).
逐个碱基套用 A-T、C-G 的碱基互补配对 (complementary base pairing):T→A,A→T,C→G,G→C,G→C,C→G,A→T,T→A,得到 A-T-G-C-C-G-T-A。B 只是把原序列照抄了一遍,是"复制成一样"而非"互补"的典型错误。C 在第 3、4 位出现了 C 对 C、G 对 G。D 在最后两位违反规则(A 对 A、T 对 T)。做题技巧:写完后回头逐位检查,只允许出现 A-T 和 C-G 两种组合。
9During DNA replication the double helix 'unzips'. Which bonds are broken when this happens?
Only the weak hydrogen bonds between paired bases are broken, which is why the two strands can separate while each strand stays intact. The sugar-phosphate backbone is held by strong covalent bonds and is NOT broken - if it were, the strand would fall apart and could not act as a template. Option C would remove bases from the strand, destroying the sequence. Option D describes a structure at the centromere, which has nothing to do with unzipping the helix.
被断开的只是配对碱基之间弱的氢键 (hydrogen bond),所以两条链能分开、而每条链本身完好无损。磷酸—脱氧核糖骨架 (sugar-phosphate backbone) 由强的共价键连接,不会断——若断了,模板链 (template strand) 就散架了,无法作模板。C 若成立会把碱基从链上摘下来,序列就被毁了。D 说的是着丝粒 (centromere) 处姐妹染色单体 (sister chromatid) 的连接,与解开双螺旋无关。可以这样记:"拉链齿(氢键)打开,拉链带(骨架)不断。"
10A micrograph of an onion root-tip cell shows the following: no nuclear envelope is visible; each chromosome is clearly made of two chromatids; all the chromosomes lie in a single line across the middle of the cell; spindle fibres run from each pole and attach to the chromosomes at their centromeres. Identify the stage of mitosis shown.
The decisive clue is that the chromosomes are aligned in a single line on the equator (metaphase plate) with spindle fibres attached at their centromeres - this is metaphase. In prophase the chromosomes are condensing but are scattered and the spindle is still forming. In anaphase the centromeres have already divided and the separated chromatids are moving towards the poles, so nothing is lined up at the equator. In telophase the chromosomes are at the poles, decondensing, and nuclear envelopes are reforming.
判定的关键证据是:染色体排成一列位于赤道板 (equator / metaphase plate) 上,且纺锤丝(纺锤体)(spindle fibre) 附着在着丝粒 (centromere) 处——这正是中期 (metaphase)。前期 (prophase) 时染色体正在螺旋化、分散排列,纺锤体尚在形成。后期 (anaphase) 时着丝粒已经分裂,分开的染色单体正向两极移动,中央不会整齐排一列。末期 (telophase) 时染色体已到两极、开始解螺旋,核膜正在重建。看图题要养成"逐条比对线索"的习惯,而不是凭印象猜。
11Which option places these structures in order from SMALLEST to LARGEST?
A base pair is a single rung of the DNA ladder; a gene is a length of DNA made of many base pairs; a chromosome is one very long DNA molecule (with its associated proteins) carrying many genes; the genome is the complete set of an organism's DNA - in humans, all 46 chromosomes. The other options invert the gene/base-pair or gene/chromosome relationship, which is the common error of treating 'gene' and 'chromosome' as interchangeable or assuming one chromosome carries one gene.
碱基对 (base pair) 是 DNA"梯子"上的一级横档,最小;基因 (gene) 是一段含有许多碱基对的 DNA;染色体 (chromosome) 是一条极长的 DNA 分子(连同相关蛋白质),上面携带许多个基因;基因组 (genome) 指一个生物体的全部 DNA——在人类即全部 46 条染色体。其余选项把基因与碱基对、或基因与染色体的大小关系颠倒了,反映的正是"把 gene 和 chromosome 当同义词"或"一条染色体只有一个基因"这类误解。
12A student examines a stained garlic root-tip squash under the microscope. Of the 250 cells counted, 40 show condensed chromosomes and spindle fibres, indicating they are undergoing mitosis. Calculate the mitotic index of this tissue.
Mitotic index = (number of cells in mitosis ÷ total number of cells counted) × 100 = (40 ÷ 250) × 100 = 16%. Option B is the result of dividing the wrong way round (250 ÷ 40). Option C simply reports the raw count as a percentage. Option D is the percentage of cells NOT in mitosis (which, usefully, tells you that most cells are in interphase at any moment).
有丝分裂指数 (mitotic index) =(处于分裂期的细胞数 ÷ 计数的细胞总数)× 100 =(40 ÷ 250)× 100 = 16%。B 是把除法做反了(250 ÷ 40 = 6.25)。C 直接把原始计数 40 当成百分数。D 是"不处于分裂期"的细胞百分比——顺带说明:任一瞬间绝大多数细胞都停在(分裂)间期 (interphase),这也印证了间期是细胞周期中最长的阶段。考试要求写出算式与百分号单位。
13A human somatic cell has just completed S phase and is now in G2. How many chromosomes and how many chromatids does this cell contain?
Replication in S phase does not change the chromosome NUMBER. Each of the 46 chromosomes is now made of two identical sister chromatids joined at a centromere, so there are 46 chromosomes but 92 chromatids. Counting chromatids as chromosomes (option B) is the single most common error in this topic: a replicated chromosome is still ONE chromosome. Option D describes a haploid number, which is not what a somatic cell has.
S 期的复制不改变染色体 (chromosome) 的数目。此时 46 条染色体中的每一条,都由 2 条完全相同的姐妹染色单体 (sister chromatid) 通过着丝粒 (centromere) 相连,所以是 46 条染色体、92 条染色单体。把染色单体当成染色体来数(选项 B)是本章最常见的错误:一条复制后的染色体仍然只算 1 条染色体,数染色体就数着丝粒。D 给的是单倍体 (haploid) 数目,体细胞是二倍体 (diploid),不适用。
14Which statement BEST explains why the two daughter cells produced by mitosis are genetically identical to each other?
The identity comes from COPYING followed by equal separation, and a full-mark answer must name both steps. Option B is the answer markers penalise: sharing DNA evenly without copying it first would give each cell only half the genetic information, not a complete identical set. Option C imports meiosis - homologous chromosomes are not paired or separated in mitosis. Option D is simply false: mitosis conserves the chromosome number.
"完全相同"来自两步:先复制、再均分,缺一不可,满分答案必须两步都写出来。选项 B 正是评分老师会扣分的写法——只"平均分配"而没有先复制,每个子细胞只会拿到一半的遗传信息,根本不可能相同。C 把减数分裂 (meiosis) 的情节搬了进来:有丝分裂中同源染色体并不配对,也不被分开。D 是错误陈述:有丝分裂维持染色体数目不变,并不减半。
15A drug completely blocks DNA replication, but a cell nevertheless enters mitosis. Predict the most likely consequence for the two daughter cells.
Mitosis only SEPARATES material that already exists; it does not copy DNA. Without S phase, every chromosome is a single unreplicated chromatid, so there is no identical partner to send to the opposite pole and the daughter nuclei cannot each receive a complete set of chromosomes. Option B is the opposite of blocking replication. Option C describes meiosis, which is not what mitosis does under any circumstances. Option D confuses cell size with genetic content - the problem is missing genetic information, not volume.
有丝分裂只负责"分开"已经存在的物质,它本身不复制 DNA。缺了 S 期,每条染色体都只有 1 条未复制的染色单体,也就没有一个完全相同的"搭档"可以送往对侧极,因此两个子细胞不可能各自获得一整套完整的染色体。B 与"阻断复制"的前提正好相反。C 描述的是减数分裂 (meiosis),有丝分裂在任何情况下都不会产生 4 个单倍体细胞。D 把细胞体积和遗传物质混为一谈——问题出在遗传信息缺失,而不是细胞变小。这道题正是"为什么复制必须在分裂之前完成"的反向验证。
0 / 15 Instant marking. Your score is saved.

Part B · Short & Extended Response 22 marks total

Write full sentences and use the proper terms — that is where the marks are.

1Describe the structure of a DNA molecule. (3 marks)3 marks
Full-mark answer

DNA is a polymer made of many nucleotides, and each nucleotide consists of a phosphate group, a deoxyribose sugar and one nitrogenous base (adenine, thymine, cytosine or guanine). The nucleotides of one strand are joined through their sugars and phosphates by strong covalent bonds, forming a sugar-phosphate backbone. Two such strands run in opposite directions (antiparallel) and are wound into a double helix, held together by weak hydrogen bonds between complementary bases: adenine always pairs with thymine (two hydrogen bonds) and cytosine always pairs with guanine (three hydrogen bonds).

得分点 Marking points:
  • 得分点 1:写出单体组成——DNA 是由核苷酸 (nucleotide) 聚合而成,每个核苷酸 = 磷酸基团 (phosphate group) + 脱氧核糖 (deoxyribose sugar) + 一个含氮碱基 (nitrogenous base),并把四种碱基 A、T、C、G 点出来。只写"由核苷酸组成"而不拆开三部分,拿不到这一分。
  • 得分点 2:写出链的骨架与整体形状——糖和磷酸通过共价键 (covalent bond) 相连形成磷酸—脱氧核糖骨架 (sugar-phosphate backbone);两条链反向平行 (antiparallel) 盘绕成双螺旋 (double helix)。这一分考的是"骨架"和"双螺旋"两个关键词。
  • 得分点 3:写出两条链之间靠什么连接——碱基互补配对 (complementary base pairing):A 配 T、C 配 G,靠弱的氢键 (hydrogen bond) 连接(A-T 两个、C-G 三个,NSW 要求写氢键数目)。注意 Describe 是"描述特征",此题不需要解释原因,但结构要点必须齐全。
2Explain why it is important that the sugar-phosphate backbone is held together by strong covalent bonds while the two strands are held together by weak hydrogen bonds. (3 marks)3 marks
Full-mark answer

Hydrogen bonds between paired bases are individually weak, so they can be broken relatively easily and the two strands can separate, or 'unzip', when the DNA needs to be replicated. Because the sugar-phosphate backbone is held by strong covalent bonds, each separated strand stays intact and its base sequence is preserved, so it can act as a template for building a new complementary strand. At the same time, a DNA molecule contains an enormous number of hydrogen bonds, so collectively they are strong enough to hold the double helix together and keep the molecule stable when it is not replicating.

得分点 Marking points:
  • 得分点 1:氢键 (hydrogen bond) 弱 → 容易断开 → 两条链可以"解开拉链"分离,使 DNA 复制 (DNA replication) 得以进行。
  • 得分点 2:共价键 (covalent bond) 强 → 磷酸—脱氧核糖骨架 (sugar-phosphate backbone) 不会断 → 每条链保持完整、碱基顺序不被破坏 → 才能作为模板链 (template strand)。这一分是本题的核心因果链,务必写出"所以能当模板"。
  • 得分点 3:数量效应——一个 DNA 分子中氢键数目极多,合起来足以维持双螺旋 (double helix) 的稳定。Explain 题的每一句都要用 because / so that / therefore 把因果串起来,只罗列"氢键弱、共价键强"而不说后果,最多得 1 分。
3Outline the events that occur in a eukaryotic cell from the beginning of G1 phase through to the completion of cytokinesis. (4 marks)4 marks
Full-mark answer

During G1 the cell grows in size, carries out normal metabolism and synthesises organelles and proteins. In S phase the DNA is replicated, so that each chromosome comes to consist of two identical sister chromatids joined at a centromere. In G2 the cell grows further and makes the proteins needed for division, including the components of the spindle, and checks that the DNA has been correctly copied. The cell then enters M phase: mitosis divides the nucleus through prophase, metaphase, anaphase and telophase, and this is followed by cytokinesis, in which the cytoplasm divides to produce two separate daughter cells.

得分点 Marking points:
  • 得分点 1:G1 期 — 细胞生长、进行正常代谢、合成细胞器 (organelle) 与蛋白质。
  • 得分点 2:S 期(合成期)— 完成 DNA 复制 (DNA replication),每条染色体变成由着丝粒 (centromere) 相连的 2 条姐妹染色单体 (sister chromatid)。这是全题最关键的一分。
  • 得分点 3:G2 期 — 继续生长,合成分裂所需的蛋白质(包括纺锤体成分),并检查 DNA 是否复制正确。
  • 得分点 4:M 期 (M phase) — 有丝分裂 (mitosis) 按前期→中期→后期→末期分裂细胞核,随后胞质分裂 (cytokinesis) 分开细胞质,形成 2 个独立子细胞 (daughter cell)。注意 Outline 只要"按顺序给出主要事件",不必展开机制;但四个阶段一个都不能漏,顺序也不能乱。
4Justify the statement that DNA replication must be completed before mitosis begins. (4 marks)4 marks
Full-mark answer

DNA replication occurs during S phase of interphase, and it is the only stage at which the genetic material is copied. Mitosis itself does not copy DNA; it only separates chromatids that already exist, because at anaphase the centromeres divide and one chromatid of each pair is pulled to each pole. Therefore, if replication had not already produced two identical sister chromatids on every chromosome, there would be no identical copy to send to each pole, and the DNA content of the daughter cells would be halved at every division so that each daughter cell would receive an incomplete set of genetic instructions. Replication before mitosis is therefore essential for producing two complete, genetically identical daughter cells, and this is why the statement is valid.

得分点 Marking points:
  • 得分点 1:指出复制发生在(分裂)间期 (interphase) 的 S 期,这是唯一复制遗传物质的阶段。
  • 得分点 2:指出有丝分裂 (mitosis) 本身不复制,只是"分开"——后期 (anaphase) 着丝粒 (centromere) 分裂,每对姐妹染色单体各有一条被拉向一极。这是 Justify 题的"证据"部分。
  • 得分点 3:写出反面后果——若未先复制,就没有相同的拷贝可分给两极,每次分裂 DNA 含量会减半,子细胞得到的遗传信息不完整。用"if...then"的假设推理来支撑论点最有力。
  • 得分点 4:给出明确结论——因此复制必须先于分裂完成,才能产生两个完整且遗传物质完全相同 (genetically identical) 的子细胞。Justify 一定要有一句收尾的判断句,只讲道理不下结论会失分。
5Compare cytokinesis in a plant cell with cytokinesis in an animal cell. (3 marks)3 marks
Full-mark answer

In both plant and animal cells, cytokinesis is a separate process that follows mitosis and divides the cytoplasm of the parent cell, producing two separate daughter cells. In an animal cell the plasma membrane is pulled inwards at the equator to form a cleavage furrow, which deepens until the cell is pinched into two. In a plant cell no furrow can form because of the rigid cell wall; instead, vesicles collect at the equator and fuse to form a cell plate, which develops into a new cell wall and membrane separating the two daughter cells.

得分点 Marking points:
  • 得分点 1:相同点 — 两者都是紧接有丝分裂 (mitosis) 之后、把细胞质分开的独立过程,结果都是形成 2 个子细胞 (daughter cell)。Compare 要求"异同都写",只写不同最多得 2 分。
  • 得分点 2:动物细胞 — 细胞膜在赤道部位向内缢缩形成分裂沟 (cleavage furrow),逐渐加深把细胞"掐断"成两个。
  • 得分点 3:植物细胞 — 因有坚硬的细胞壁无法内缢,改由囊泡在赤道处聚集融合形成细胞板 (cell plate),进而发育成新的细胞壁和细胞膜。写出"因为有细胞壁"这个原因能让答案更完整。答题格式建议用同一标准逐条对照(先说共同点,再用 whereas 对比两者)。
6Explain how mitosis produces two genetically identical daughter cells. Use correct biological terminology in your answer. (5 marks)5 marks
Full-mark answer

Before mitosis begins, the DNA is replicated semi-conservatively during S phase of interphase: the double helix unzips as the hydrogen bonds between complementary bases break, each original strand acts as a template, and free nucleotides pair complementarily with it, so that each new DNA molecule contains one original and one new strand and is an exact copy of the original. As a result, each chromosome now consists of two identical sister chromatids joined at a centromere. In prophase the chromosomes condense and become visible, the nuclear envelope breaks down and spindle fibres form; in metaphase the chromosomes line up on the equator with spindle fibres attached at their centromeres. At anaphase the centromeres divide and the spindle fibres pull one chromatid of each pair to each pole, so each pole receives one complete copy of every chromosome. In telophase the chromosomes decondense and a nuclear envelope reforms around each set, and cytokinesis then divides the cytoplasm, producing two diploid daughter cells that are genetically identical to each other and to the parent cell.

得分点 Marking points:
  • 得分点 1:复制这一步 — 说明在(分裂)间期 (interphase) 的 S 期进行半保留复制 (semi-conservative replication):氢键 (hydrogen bond) 断裂使双螺旋解开,原有链作模板链 (template strand),游离核苷酸按碱基互补配对 (complementary base pairing) 结合,新分子=一旧链+一新链,因而是精确拷贝。缺这一步的答案(只说"平均分配 DNA")会被判为关键遗漏。
  • 得分点 2:复制的结果 — 每条染色体由 2 条完全相同的姐妹染色单体 (sister chromatid) 组成,在着丝粒 (centromere) 处相连。
  • 得分点 3:前期与中期 — 前期 (prophase) 染色体螺旋化变得可见、核膜 (nuclear envelope) 解体、纺锤丝(纺锤体)(spindle fibre) 形成;中期 (metaphase) 染色体排列在赤道板 (equator) 上,纺锤丝附着于着丝粒(注意:附着点是着丝粒,不是染色体末端)。
  • 得分点 4:后期是"相同"的关键机制 — 后期 (anaphase) 着丝粒分裂,每对姐妹染色单体各有一条被拉向相反的极,因此每一极都获得每条染色体的一份完整拷贝。
  • 得分点 5:收尾 — 末期 (telophase) 染色体解螺旋、两个新核膜重建,随后胞质分裂 (cytokinesis) 分开细胞质,形成 2 个二倍体 (diploid)、彼此及与亲代细胞遗传物质完全相同 (genetically identical) 的子细胞。Explain 题要求因果成链:用 so that / because / therefore 把"复制→相同的姐妹染色单体→着丝粒分裂→各得一份→完全相同"一路串到底。

Part C · Name the Term 12 definitions

Read the definition and write the term it describes.

1DNA is the molecule found inside the nucleus of a cell that stores the genetic instructions for building and running an organism.DNA
2Deoxyribonucleic acid is the full chemical name for DNA: a nucleic acid built from many repeating nucleotide units, each containing a deoxyribose sugar.deoxyribonucleic acid
3A nucleotide is the repeating building block (monomer) of DNA, made of a phosphate group, a deoxyribose sugar and one nitrogenous base.nucleotide
4The cell cycle is the ordered sequence of events in which a cell grows, copies its DNA and then divides to produce two new cells.cell cycle
5Interphase is the longest part of the cell cycle, made up of G1, S and G2, during which the cell grows, carries out its normal functions and replicates its DNA — it is not a resting phase.interphase
6G1, the first gap phase, is the part of interphase after division in which the cell grows, makes proteins and new organelles, and prepares for DNA replication.G1 phase
7DNA replication is the process in which a DNA molecule is copied to produce two identical molecules; it happens during S phase of interphase, before mitosis begins.DNA replication
8Semi-conservative replication means each new DNA molecule keeps one original (parent) strand and one newly built strand.semi-conservative replication
9A template strand is an original strand of DNA whose base sequence is read to determine the sequence of the new complementary strand.template strand
10Prophase is the first stage of mitosis, in which chromatin condenses into visible chromosomes (each already made of two sister chromatids), the spindle begins to form and the nuclear envelope breaks down.prophase
11Metaphase is the stage in which the chromosomes are lined up along the equator of the cell, attached to spindle fibres at their centromeres.metaphase
12Anaphase is the stage in which the centromeres split and the spindle fibres pull the sister chromatids to opposite poles, so each pole receives an identical set.anaphase
← Back to
Day 4